关于来电响铃半声即断的协议,进来看看,,,,^_^ [CS-ID:9E02C14E714] / [PS-ID:018356864] || 0.00000||0 < PS SCCH: 0102020800 77dBuV || 462.49833||0 > CS SCCH: 0106010801 51dBuV (Assigned: Abs.Slot 3 / CarrierNo. 8) || 520.62375||0 < PS SYNC: 0000000000 78dBuV || 523.12250||0 > CS SYNC: 0000000000 48dBuV || 530.43667||0 --<< Sync off || 530.43667||0 -<- Idle TCH [8000FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF] || 532.93583||0 -->> Sync off || 532.93583||0 ->- Idle TCH [80000000000000000000000000000000000000000000] || 610.43667||0 <[4306] <RT PRs RT [PS Identity:0F11512AAA185160] || 872.93583||0 >[45010405] >CC SETUP CC [Bearer Capability:0403808CA4] CC [Calling Party number:6C0A00803638323935363730] CC [Called Party number:700D80313531323030303138353136] || 900.43667||0 <[45018402] <CC CALL PROC || 935.43625||0 <[4301] <RT DIRq RT [Definition Info.Req.:81] || 982.93542||0 >[4302] >RT DIRs RT [Area Info.:013C3840422C3003] || 995.43667||0 <[4304] <RT FRq RT [Encryption:091000] RT [TCH Reassign:1517] RT [Zone Info.Indicat.Func.:C0] || 1027.93542||0 >[4305] >RT FRs RT [Encryption:091000] RT [TCH Reassign:1517] RT [Zone Info.Indicat.Func.:C0] || 1040.43625||0 <[4303] <RT EKS RT [Encryption Key Set:0D022618] || 1112.93542||0 >[4401] >MM ARq MM [Authentication Type:0601] MM [Authentication Random Pattern:07084BCF718A56A793FB] || 1247.93542||0 -->> TX on || 1330.43583||0 <[4402] <MM ARs MM [Active Chipherring Pattern:0508C709FA3005063B60] || 1430.43625||0 <[45018401] <CC ALERT || 2222.93417||0 -->> TX on || 3112.93375||0 >[45010445] >CC DISC CC [Cause:0803028590] || 3140.43417||0 <[4501844D] <CC REL || 3282.93375||0 >[4501045A] >CC REL COMP || 3342.93333||0 >[4322] >RT RDi RT [Cause:0680] RT [CS Ident.:089E02C14E7101] RT [PS Ident.:0E1181A800] || 3355.43417||0 <[4323] <RT RDiC RT [CS Ident.:089E02C14E7101] RT [PS Ident.:0E1181A800] || 3490.63250||0 --<< TX off || 3503.13250||0 ->>< TX off 疑点:1.CC ALERT后会有个下行下TX ON? 2.下行下TX ON后为什么又会下行的CC DISC? 3.Cause:0803028590解析出来是Normal call clearing,还有没有其他的含义?? 有请高手解答~~~~ |